Speed, distance and time
Driving 60 km out at 60 km/h and back at 40 km/h averages 48 km/h, not 50.
Out at 60 km/h, back at 40. What is the average?
Answer this before reading further. You drive 60 km to a town at 60 km/h and drive the same road back at 40 km/h. What was your average speed for the whole trip? If you wrote 50, keep that number nearby. It is the obvious answer, and it is wrong. By the end of the page the real answer, 48, should look obvious too.
150 km in 2 hours is 75 km in one
A train covers 150 km in 2 hours. Its average speed is the distance per one hour: 150 ÷ 2 = 75 km/h. Speed is the most familiar unit rate there is, and OpenStax uses it as the example when it introduces unit rates: 68 miles per hour means 68 miles in 1 hour. Any unit of distance over any unit of time works: metres per second, kilometres per hour, miles per hour.
d = rt, and the two ways to rearrange it
OpenStax writes the formula for an object moving at a constant speed as d = rt: distance equals rate times time. Solve it for the other letters and you get r = d/t and t = d/r. At 70 km/h for 3 hours you cover 70 × 3 = 210 km. To cover 210 km at 70 km/h takes 210 ÷ 70 = 3 hours. And 210 km in 3 hours is 210 ÷ 3 = 70 km/h. The three forms are the same fact seen from different sides.
45 minutes is 0.75 hours, not 0.45
Minutes and hours are easy to mix up. A cyclist rides 30 km in 45 minutes. 30 ÷ 45 gives 0.667 km per minute, which is correct but is not km/h. Change the time to hours first: 45 minutes is 45/60 = 0.75 hours, and 30 ÷ 0.75 = 40 km/h. Going the other way, 1.2 hours is not 1 hour 20 minutes. It is 1 hour and 0.2 × 60 = 12 minutes. A made-up ride to school, 3 km in 15 minutes, works the same way: 15 minutes is 0.25 hours, so 3 ÷ 0.25 = 12 km/h.
Runners often use pace, the rate turned upside down: minutes per kilometre. A pace of 5 minutes per km means 60 ÷ 5 = 12 km in an hour, so 12 km/h. For speeds in metres per second, multiply by 3,600 seconds in an hour and divide by 1,000 metres in a kilometre, which is the same as multiplying by 3.6: 10 m/s is 36 km/h.
Average speed is not the average of the speeds
You drive 60 km to a town at 60 km/h and come back the same 60 km at 40 km/h. The average of 60 and 40 is 50, but that is not your average speed. Find total distance over total time. Going takes 60 ÷ 60 = 1 hour; returning takes 60 ÷ 40 = 1.5 hours. Total: 120 km in 2.5 hours, so 120 ÷ 2.5 = 48 km/h. The slow leg lasts longer, so it pulls the average down more.
60 mph is about 97 km/h
NIST Handbook 44 lists 1 mile as exactly 1.609344 kilometres. A speed of 60 miles per hour is 60 × 1.609344 = 96.56 km/h, about 97. For a rough figure in your head, multiply miles by 1.6, or multiply kilometres by 5/8 to get miles: 80 km/h is about 50 mph.
| distance | d = r × t |
| rate (speed) | r = d ÷ t |
| time | t = d ÷ r |
| m/s to km/h | multiply by 3.6 |
| 1 mile | 1.609344 km exactly (NIST) |
- 180 km in 3 hours. Average speed?
- At 80 km/h, how far in 2.5 hours?
- How many hours to cover 390 km at 65 km/h?
- 18 km in 40 minutes. Speed in km/h?
- At 48 km/h, how many minutes for 12 km?
- A pace of 4 minutes per km is what speed in km/h?
- 25 m/s in km/h?
- You walk 6 km to a lake at 6 km/h and back at 4 km/h. Average speed?
- 50 miles per hour in km/h, to one decimal place? (1 mile = 1.609344 km)
- How long is 2.3 hours?
- 2 h 30 min
- 2 h 18 min
- 2 h 3 min
- Out at 30 km/h, back the same 30 km at 10 km/h: "average 20 km/h". Use total distance over total time. 1 hour out, 3 hours back: 60 km ÷ 4 h = 15 km/h.
- 10 km in 20 minutes: "10 ÷ 20 = 0.5 km/h". 0.5 is km per minute. 20 minutes is 1/3 hour, so 10 ÷ 1/3 = 30 km/h.
- 1.5 hours written as 1 hour 50 minutes. The decimal is a part of an hour. 0.5 × 60 = 30, so 1 hour 30 minutes.
- 20 m/s turned into km/h by dividing by 3.6: about 5.6 km/h. A metre per second is faster than a kilometre per hour, so the km/h number must be bigger. Multiply: 20 × 3.6 = 72 km/h.
- d = rt, r = d/t, t = d/r.
- Change minutes to hours (÷ 60) before using km/h.
- Average speed = total distance ÷ total time.
- 1 mile = 1.609344 km exactly; m/s × 3.6 = km/h.
Sources for this course (11)
- Curriculum: 교육부 고시 제2022-33호 [별책 8] 수학과 교육과정 (ncic.re.kr/inv/org/download.do?year=2022&seq=10003559&orgType=ogi4, PDF read 2026-10-19: 초등학교 3~4학년군 [4수03-16] 1 cm와 1 mm, 1 km와 1 m의 관계; 5~6학년군 [6수01-09] 분수의 곱셈, [6수02-02] 비, [6수02-03] 비율, [6수02-04] 비례식, [6수02-05] 비례배분, 용어 비·기준량·비교하는 양·비율·백분율·비례식·비례배분·:·%; 중학교 1~3학년군 [9수02-07] 정비례·반비례(해설: 속력과 거리, 속력과 시간), [9수03-12] 닮음비; 고등학교 진로 선택 직무 수학 [12직수02-01] 해설 단위가격·단가, [12직수03-03] 해설 지도의 축척)
- Textbook: OpenStax, Prealgebra 2e (Marecek, Anthony-Smith, Honeycutt Mathis, 2020)
- sections 5.6 Ratios and Rate, 6.5 Solve Proportions and their Applications (Key Concepts)
- 9.7 Use the Distance, Rate, and Time Formula (openstax.org/books/prealgebra-2e/pages/5-6-ratios-and-rate, /6-key-concepts, /9-7-solve-a-formula-for-a-specific-variable, checked 2026-10-17)
- Textbook companion: EBS 『만점왕 수학 6-1』 4. 비와 비율 (2020, 2015 개정 교육과정 교과서 학습서; livedown2.ebs.co.kr/ebsvod/elmt/live/만점왕수학6-1-4주.pdf, checked 2026-10-19: 기호 :의 오른쪽이 기준량, 「~에 대한」 읽기, 걸린 시간에 대한 간 거리의 비율, 비율이 쓰이는 예로 지도의 축척)
- USGS Fact Sheet 015-02 "Map Scales" (pubs.usgs.gov/fs/2002/0015/report.pdf, checked 2026-10-17)
- USGS FAQ "Why are USGS topographic maps called quadrangles?" (usgs.gov/faqs, checked 2026-10-17)
- NIST Handbook 44 Appendix C, 1 mile = 1.609344 km and 1 inch = 2.54 cm exactly (nist.gov, checked 2026-10-17)
- 산업통상자원부 보도자료 「산업부, 가격표시제 실시요령 개정」 2025-04-02 (motir.go.kr, 단위가격 표시품목 84개 → 114개, checked 2026-10-19)
- 교육부 공식 블로그 「이상한 지하철 노선도」 2016-02-02 (if-blog.tistory.com/6161, 서울 지하철 1호선 노선도와 실제 노선 비교, checked 2026-10-19)
- History block only: USGS FAQ "When was the 1:24,000-scale topographic map series completed?" (usgs.gov/faqs, checked 2026-10-17)
Checked: 2026-10-17