Cylinders
Peel the label off a tin can and it lies flat as a rectangle whose width is the can's circumference, 2πr.
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Cut a paper tube straight down
Find an empty toilet-roll tube and a pair of scissors. Cut once, straight down from top to bottom, and flatten it. You get a rectangle. Its height is the height of the tube. Its width? That is the distance once around the circle, the circumference, 2πr. The model does the same when you press Unfold: the curved side opens at the back seam, keeps its width while the curve straightens out, and finishes with the two circles touching the long edges of the rectangle.
The side is a rectangle 2πr wide and h tall
So the curved surface, the part that stops most people, has area 2πr × h = 2πrh. Add the two circles at the ends and you have the whole surface: A = 2πr² + 2πrh, which can also be written 2πr(r + h). The model's cylinder starts at r = 2 cm and h = 5 cm, so its surface is 8π + 20π = 28π ≈ 87.96 cm².
Real objects do not always have both circles. A cup without a lid has only a bottom, so its surface is πr² + 2πrh. A pipe or a cardboard tube has no circles at all, and only 2πrh counts. In a real problem, half the work is reading which surfaces are actually there.
Back to labels. A label for a can of radius 4 cm and height 10 cm has area 2π × 4 × 10 = 80π ≈ 251.3 cm². It must be 2π × 4 ≈ 25.1 cm wide, and a little more in practice so the ends can overlap and be glued. The same rectangle turns up whenever something is wrapped around a cylinder: the card inside a toilet roll, a sheet of metal rolled into a pipe, a poster round a column.
Volume follows the prism rule with a circle for a base
A cylinder has two identical, parallel circular bases and the same cross-section all the way between them. That is the prism idea again, so V = base area × height = πr²h. For r = 2 cm and h = 5 cm, V = π × 4 × 5 = 20π ≈ 62.83 cm³. The symbol π is the ratio of any circle's circumference to its diameter, about 3.14159. Leave answers as multiples of π, like 20π, and turn them into decimals only at the end, so that rounding errors have no chance to pile up along the way.
Radius matters more than height. Double the height and the volume doubles. Double the radius and the base area becomes four times larger, so the volume does too. Set r = 2 in the model and note the volume, then try r = 4 with the same height. This is why a slightly wider cup holds much more than a slightly taller one.
- Putting the diameter where the radius belongs: a can 4 cm across gives π × 4² × 5. 4 cm across means r = 2 cm. Using 4 doubles the radius, so the volume comes out four times too big: 80π instead of 20π.
- Writing the curved side as πr × h or 2r × h. The unrolled side is as wide as the whole circumference, 2πr. πr is half of it, and 2r is just the diameter.
- Adding two circles for an open cup or a pipe. Count only the surfaces that exist. An open cup has one circle and a pipe has none.
- Rounding π at the first step and again at every step after it. Small rounding errors grow as you go. Keep π until the last line, then round once.
- Volume of a cylinder with r = 2 cm and h = 5 cm (to 2 decimal places)?
- Total surface area of the same cylinder?
- The side of a cylinder with r = 5 cm is unrolled. How wide is the rectangle?
- Label area for a can with r = 4 cm, h = 10 cm (no overlap)?
- A pot has r = 10 cm and h = 20 cm. About how many litres does it hold?
- Doubling the radius of a cylinder (same height) multiplies its volume by…
- The net of a cylinder is made of…
- a rectangle and two circles
- a sector and a circle
- three rectangles and two triangles
- A cylinder has volume 100π cm³ and height 4 cm. What is its radius?
- Surface area of an open cup (no lid) with r = 3 cm, h = 8 cm?
- Cylinder volume: πr²h.
- Curved side unrolls into a rectangle 2πr × h.
- Total surface: 2πr² + 2πrh.
- Radius matters more than height: double r, four times the volume.
Sources for this course (8)
- (checked 2026-10-17; reordered 2026-10-19: curriculum and textbooks first, then reference works and units, history last)
- Curriculum: 교육부 고시 제2022-33호 [별책 8] 수학과 교육과정 (ncic.re.kr/inv/org/download.do?year=2022&seq=10003559&orgType=ogi4, PDF read 2026-10-19: 초등학교 5~6학년군 [6수03-03]~[6수03-08] 직육면체·정육면체·각기둥·각뿔·원기둥·원뿔·구, 원기둥의 전개도, "각뿔과 원뿔의 전개도는 다루지 않는다", 원주율의 근삿값 3.14, [6수03-17]~[6수03-19] 직육면체와 정육면체의 겉넓이, 1cm³·1m³, 부피; 3~4학년군 [4수03-17] 들이 1L·1mL; 중학교 1~3학년군 [9수03-06] 부채꼴, [9수03-07] 다면체와 회전체, [9수03-08] 입체도형의 겉넓이와 부피, 도형의 닮음·닮음비; 오일러 공식은 성취기준에 이름으로 없음)
- Textbook: OpenStax Prealgebra 2e, 9.6 Solve Geometry Applications: Volume and Surface Area (openstax.org/books/prealgebra-2e/pages/9-6-solve-geometry-applications-volume-and-surface-area)
- Reference: Wolfram MathWorld, Polyhedral Formula (mathworld.wolfram.com/PolyhedralFormula.html)
- AMS Feature Column, Euler's Polyhedral Formula (ams.org/publicoutreach/feature-column/fcarc-eulers-formula)
- BIPM SI Brochure and NIST SI Units - Volume (litre and cubic metre)
- History block only: MacTutor, Archimedes biography (On the Sphere and Cylinder, sphere = 2/3 of the circumscribed cylinder, the figure on his tomb, Cicero's search; mathshistory.st-andrews.ac.uk/Biographies/Archimedes/)
- MacTutor, A history of Topology (Euler's 1750 letter to Goldbach with v − e + f = 2; mathshistory.st-andrews.ac.uk/HistTopics/Topology_in_mathematics)
Checked: 2026-10-17