Pyramids and cones
A cone of water poured into a cylinder with the same base and height fills it exactly one third of the way.
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"A cone is half a cylinder" sounds right and is wrong
Stand an ice cream cone next to a straight-sided glass of the same width and height, and ask how much of the glass the cone would fill. The tempting answer is half. It looks like half, because the cone starts as wide as the glass and narrows steadily to nothing. But the narrow part near the tip holds very little. Pour water from a full cone into the matching cylinder and it fills exactly one third. Three full cones fill the cylinder.
The rule covers every pointed solid. A pyramid has a polygon for a base and triangles for sides; a square pyramid has a square base and four triangles. A cone has a circle for a base and one curved side. Both narrow to a single point, the apex, and for both V = ⅓ × base area × height. A square pyramid has V = ⅓ a²h, and a cone has V = ⅓ πr²h. Teachers often show the rule with water or sand. A real proof needs calculus or a clever cutting argument, but you can repeat the pouring test at home with paper cones.
Which height goes into the formula
The second trap is the height. In V = ⅓ Bh, h is the perpendicular height, measured straight up from the base to the apex. The sloping distance along a face is a different length, the slant height, and it belongs to surface area. For a square pyramid the slant height is the height of each triangular face, from the middle of a base edge up to the apex. A right triangle hides inside the pyramid. One leg is the height h, the other is half the base, a/2, and the hypotenuse is the slant height s, so by Pythagoras s = √(h² + (a/2)²).
In the model, a = 6 cm and h = 4 cm, so s = √(16 + 9) = 5 cm. Each triangle is ½ × 6 × 5 = 15 cm², the four of them make 60 cm², and with the 36 cm² base the whole surface is 96 cm². Put 5 into the volume formula instead of 4 and the answer is wrong.
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A cone opens into a slice of pizza
Unroll the side of a cone and you get a sector, a slice of a circle shaped like a piece of pizza. Its radius is the cone's slant length l = √(r² + h²). Its curved edge wraps once around the base, so the arc has to be as long as the base circumference, 2πr. A whole circle of radius l would measure 2πl around. The sector is therefore the fraction r/l of that circle, with an angle of 360° × r/l. For r = 3 and l = 5 the angle is 360° × 3/5 = 216°, and the area is (r/l) × πl² = πrl = 15π.
Add the base and the whole surface of a cone is A = πr² + πrl. For the model cone that is 9π + 15π = 24π ≈ 75.4 cm², and its volume is ⅓ × π × 9 × 4 = 12π ≈ 37.7 cm³. An ice cream cone has no lid, so the wafer is only the πrl part. Party hats, traffic cones and funnels are cut from sectors in the same way. The designer chooses the angle 360° × r/l to get the width wanted at the bottom.
- Leaving out the ⅓: for r = 3 and h = 4, cone volume = πr²h = 36π. That is the volume of the matching cylinder. The cone holds a third of it, 12π ≈ 37.7 cm³.
- Multiplying by ½ because a cone looks like half a cylinder. The tip holds very little. Both the pouring test and the formula give one third.
- Putting the slant height into the volume: ⅓ × 36 × 5 for the model pyramid. Volume needs the perpendicular height, 4 cm. The 5 cm slant height is for the triangles in the surface.
- Forgetting the base of a closed cone, or adding one to an ice cream cone. A solid cone has πr² + πrl. A wafer cone is open at the top, so it is only πrl.
- Square pyramid: base 6 cm, height 4 cm. Slant height?
- Surface area of that pyramid?
- Volume of that pyramid?
- Cone with r = 3 cm and h = 4 cm: volume (2 decimal places)?
- Total surface area of the same cone?
- A cone has r = 6 cm and slant l = 10 cm. Angle of its unrolled sector?
- How many full cones fill a cylinder with the same base and height?
- Pyramid with base 10 cm × 10 cm and height 12 cm: surface area?
- Volume of that pyramid?
- Which height goes into V = ⅓ Bh?
- The perpendicular height from base to apex
- The slant height along a face
- The length of a side edge
- Pyramids and cones: V = ⅓ × base area × height.
- Square pyramid: A = a² + 2as with s = √(h² + (a/2)²).
- Cone: A = πr² + πrl with l = √(r² + h²).
- Cone side unrolls into a sector of angle 360° × r/l.
Sources for this course (8)
- (checked 2026-10-17; reordered 2026-10-19: curriculum and textbooks first, then reference works and units, history last)
- Curriculum: 교육부 고시 제2022-33호 [별책 8] 수학과 교육과정 (ncic.re.kr/inv/org/download.do?year=2022&seq=10003559&orgType=ogi4, PDF read 2026-10-19: 초등학교 5~6학년군 [6수03-03]~[6수03-08] 직육면체·정육면체·각기둥·각뿔·원기둥·원뿔·구, 원기둥의 전개도, "각뿔과 원뿔의 전개도는 다루지 않는다", 원주율의 근삿값 3.14, [6수03-17]~[6수03-19] 직육면체와 정육면체의 겉넓이, 1cm³·1m³, 부피; 3~4학년군 [4수03-17] 들이 1L·1mL; 중학교 1~3학년군 [9수03-06] 부채꼴, [9수03-07] 다면체와 회전체, [9수03-08] 입체도형의 겉넓이와 부피, 도형의 닮음·닮음비; 오일러 공식은 성취기준에 이름으로 없음)
- Textbook: OpenStax Prealgebra 2e, 9.6 Solve Geometry Applications: Volume and Surface Area (openstax.org/books/prealgebra-2e/pages/9-6-solve-geometry-applications-volume-and-surface-area)
- Reference: Wolfram MathWorld, Polyhedral Formula (mathworld.wolfram.com/PolyhedralFormula.html)
- AMS Feature Column, Euler's Polyhedral Formula (ams.org/publicoutreach/feature-column/fcarc-eulers-formula)
- BIPM SI Brochure and NIST SI Units - Volume (litre and cubic metre)
- History block only: MacTutor, Archimedes biography (On the Sphere and Cylinder, sphere = 2/3 of the circumscribed cylinder, the figure on his tomb, Cicero's search; mathshistory.st-andrews.ac.uk/Biographies/Archimedes/)
- MacTutor, A history of Topology (Euler's 1750 letter to Goldbach with v − e + f = 2; mathshistory.st-andrews.ac.uk/HistTopics/Topology_in_mathematics)
Checked: 2026-10-17